A boy crosses a river twice
on a straight graph at an
angle - 30" with the
downstream direction,
first time in two minutes
and second time in four
minutes. If his speed
relative to river current is
2. = 3 m/s in both the
attempts, find speed of
the river current.
Answers
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River velocity vs.
r =2 I r =2 I r =2 I r =2 I
The swimmer's velocity in relation to the river is v
s =5cos30 I +5sin30 j s =5cos30 I +5sin30 j s =5cos30 I +5sin30
=4.33 i ^ +2.5 i ^
Using v
R= v
s+ v
r, we get v
R=2.33 i ^ +2.5 j ^
Time taken by the swimmer= ycomponentofvelocity Distancealongy−axis
= 2.5 200=80s
Distance moved along x-axis, O ′ F=x component of relative velocity × time. =2.33×80=186.4m 186m upstream
Explanation:
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