Question

a boy cut a sector containing an angle of 140 from a circle of radius 15 cm

Answer 1

Area of sector

$= > \frac{\pi {r}^{2}o }{360}$

$= > \frac{ \frac{22}{7} \times 15 \times 15 \times 140}{360}$

$= > 22 \times 15 \times \times 15 \times 18$

$= > 89100 {cm}^{2}$

Hope this answer is helpful

Answer 2

The area of sector is  275 $cm^{2}$.

Step-by-step explanation:

We have,

The radius of circle (r) = 15 cm and

Sector angle($\theta$ = 140°

To find, the area of sector = ?

We know that,

The area of sector =$\dfrac{\theta}{360} \pi r^{2}$

$=\dfrac{140}{360} \times \dfrac{22}{7} 15\times 15$

$=\dfrac{14}{36} \times \dfrac{22}{7} \times 15\times 15$

$=\dfrac{2}{12} \times \dfrac{22}{1} \times 5\times 15$

$=\dfrac{1}{3} \times \dfrac{11}{1} \times 5\times 15$

$=\dfrac{11}{1} \times 5\times 5$

= 55 × 5 = 275 $cm^{2}$

Hence, the area of sector is  275 $cm^{2}$.