Question

A boy drives his scooter with a uniform speed of 45 km h 1. Find (i) the distance covered by him in 1 hour 20 min.(ii) the time taken by him to cover 108 km (iii) the time taken to cover 900 m
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Answer 1

Explanation:

Speed of the boy = 45km/ hr

distance travelled by the boy in 1hr/ 60min= 45km

distance travelled in 1 minute =

$\frac{45}{60 } = \frac{3}{4} \: km = 0.75km \: or \: 750 \: m$

1)

distance cover in 20 min=

$\frac{3}{4} \times 20 = 15 \: km$

DISTANCE TRAVELLED IN 1 HOUR 20 MINS=

45 KM + 15 KM = 60 KM

2)

$time = \frac{distance}{speed}$

distance=108 km, speed = 45km/ hr

$Time \: = \frac{108}{45} = \frac{12}{5} = 2.4 \: hr$

3)

distance=900m = 0.9km , speed = 45km/ hr

$Time \: = \frac{0.9}{45} = \frac{9}{45 \times 10} = \frac{1}{50} = 0.02 \: hours \: or \: 1.2 \: mins$

Answer 2

Answer:

Speed of the boy = 45km/hr

distance travelled by the boy in 1hr/ 60min= 45km

distance travelled in 1 minute =

45 60 * km = 0.75km or 750 m

1)

distance cover in 20 min=

3 x 20 = 15 km

4 DISTANCE TRAVELLED IN 1 HOUR 20 MINS=

45 KM + 15 KM = 60 KM

2)

time

distance speed

distance=108 km, speed = 45km/hr

Time 108 45 5 2.4 hr

3)

distance=900m = 0.9km, speed =

45km/hr

0.9

9 45 45 x 10 50 0.02 hours or 1.2 mins

Explanation:

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