Physics, asked by 778699jawad, 9 months ago

A boy drops a ball from 40m high building. If value of g=9.8m/s^2 then find the speed of the ball just before striking the ground.​

Answers

Answered by avadhoot1122
1

Explanation:

Height=40m

g=9.8m/s2

As ball has no initial velocity,it will fall freely...

V2-u2=2as

here,u=0,a=g and s=h

v2-0=2×9.8 ×40

v2=784

v=28m/s

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