A boy drops a coin from the top of building which is 49 m find the velocity with which the coin strikes the ground
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Answer:
Answer is 31m/s
Explanation:
as the coin is being dropped, u=0
given height is 49m
so from the kinematic equations,
h=1/2 gt²
49 = 1/2 × 9.8 × t²
t²=10 ⇒t=√10
Now from the equation v=u+gt
v=0+ 9.8×√10
= 30.98≅ 31m/s
You can also do this problem directly by using the formula v²-u²=2gh
in both ways answer will be the samee....
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