A boy drops a coin from the top of the building which is 49m.high find the velocity of the coin (I want step by step answer)
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As per energy conservation
potential energy at height h = kinetic energy at ground
mgh = (mv^2)/2
gh = v^2/2
v^2 = 2gh
v = √(2gh
v = √( 2×9.8×49
v = 30.99 m/s
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