Question

a boy drops a stone from a Cliff Reaches on the ground in 8 seconds calculate the final velocity of the stones and height of the Cliff

Answer 1

For a freely falling body, v=u+gt. =0+(9.8×8) =78.4 m/s    Now, the distance travelled by the stone is the height of the cliff. So, s=ut+(1/2)gt^2 =0+.5×9.8×8^2 =627.7 m