a boy drops a stone from the top of a building 100m high. another boy throws an iron ball, with certain velocity, 2 second later the stone was dropped. calulate the velocity with which iron ball was thrown , so that both the ball and the stone strike the ground at the same time.
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Answer:
yes because the stone is dropped there is no force and the iron ball is throwned there is force because the stone take 100s then the iron ball take 50=100 divided 2= 50
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For the motion of Stone:-
- .
Where,
S= Distance
u= Initial Velocity
t =Time
g= Acceleration due to gravity..
Now,
For the motion of iron ball
- .
Time taken by the ball to reach the ground= 4.52-2=2.52s( As it is thrown after 2 second the stone dropped)
- Now, We will find out the Initial Velocity of the iron ball.
Where,
S= Distance
u= Initial Velocity
t =Time
g= Acceleration due to gravity..
Thus, The iron ball must be thrown with the velocity of 27.33m/s^-1.
MORE TO KNOW:-
- When a Body is dropped freely from a height,it's initial Velocity 'u' is zero.
- When a Body is thrown Vertically Upwards,then at maximum height it Final velocity 'v' is zero.1
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