Science, asked by akshayraj7992, 11 months ago

a boy drops a stone from the top of a building 100m high. another boy throws an iron ball, with certain velocity, 2 second later the stone was dropped. calulate the velocity with which iron ball was thrown , so that both the ball and the stone strike the ground at the same time.

Answers

Answered by deepu0000
1

Answer:

yes because the stone is dropped there is no force and the iron ball is throwned there is force because the stone take 100s then the iron ball take 50=100 divided 2= 50

Answered by Anonymous
12

\huge\bigstar\rm\blue{ANSWER}\bigstar

\huge\bigstar\rm\blue{GIVEN}\bigstar

For the motion of Stone:-

  • \rm{Initial\:Velocity(u)=0m/s^-1}

  • \rm{Distance\:travelled(S)=100m}

  • \rm{Acceleration\:of\:Stone=9.8m/s^{-2}}.

\huge\bigstar\rm\blue{Formulae\:Used}\bigstar

  • {\boxed{\rm{\blue{S=ut+\dfrac{1}{2}g(t)^2}}}}

Where,

S= Distance

u= Initial Velocity

t =Time

g= Acceleration due to gravity..

Now,

\implies\rm{S=ut+\dfrac{1}{2}g(t)^2}

\implies\rm{100m=0+\dfrac{1}{2}\times{9.8}\times{t}^2}

\implies\rm{t^2=\dfrac{200}{9.8}}

\implies\rm{t^2=\sqrt{20.4}}

\implies\rm{t=4.52s}

For the motion of iron ball

  • \rm{Initial\:Velocity(u)=0m/s^-1}

  • \rm{Distance\:travelled(S)=100m}

  • \rm{Acceleration\:of\:Stone=9.8m/s^{-2}}.

Time taken by the ball to reach the ground= 4.52-2=2.52s( As it is thrown after 2 second the stone dropped)

  • Now, We will find out the Initial Velocity of the iron ball.

\huge\bigstar\rm\blue{Formulae\:Used}\bigstar

{\boxed{\rm{\blue{S=ut+\dfrac{1}{2}g(t)^2}}}}

Where,

S= Distance

u= Initial Velocity

t =Time

g= Acceleration due to gravity..

\implies\rm\green{S=ut+\dfrac{1}{2}g(t)^2}

\implies\rm\green{100=u\times{2.52}+\dfrac{1}{2}\times{9.8}\times{2.52}^2}

\implies\rm\green{100=2.52u+4.9\times{6.35}}

\implies\rm\green{100=2.52u+31.12}

\implies\rm\green{2.52u=100-31.12}

\implies\rm\green{u=\dfrac{68.88}{2.52}}

\implies\rm\green{u=27.33m/s^{-1}}

Thus, The iron ball must be thrown with the velocity of 27.33m/s^-1.

MORE TO KNOW:-

  • When a Body is dropped freely from a height,it's initial Velocity 'u' is zero.

  • When a Body is thrown Vertically Upwards,then at maximum height it Final velocity 'v' is zero.1
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