Question

a boy drops a stone from the top of a building and it takes 1 second to reach ground.If g=10 m/s², calculate the height of the building
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Answer 1

Answer:

5 m

Explanation:

In the given situation, stone is initially at rest, where its velocity is 0.

When it dropped, gravitational force acts on it, and, gives an acceleration of g.

Let the height be 'h'.

Using S = ut + (1/2) at^2.

 Here, u = 0  ,  t = 1 ,   a = g = 10m/s^2

⇒ S = (0)1 + (1/2)(g)(1)^2

      = 0 + (1/2)(10)(1)

      = 5 m

Answer 2

u = 0 m/s

t = 1 s

g = 10 m/s²

s = ut + ½at²

» s = 0 + ½(10)(1)²

» s = 5 m