Question

a boy drops a stone from the top of a building100high. another boy throws an iron ball 2 seconds after the stone was dropped. calculate the velocity with which the iron ball was thrown so that both the stone and the iron ball strike the ground at the same time.

Answer 1

Time taken for the stone to reach the ground can be calculated by this formula;

s=ut+½at²

100=0(t)+½(9.81)(t)²

t≈√20.38

The ball was 2seconds behind the stone so it must take time 2 seconds less than the ball to reach the ground together.

So,

s=ut+½at²

100=u{√(20.38)-2}+½(9.81){√(20.38)-2}²

u≈8.84 m/s

So the iron ball must be thrown at 8.84 m/s to reach the ground with the stone.

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Answer 2

Answer:

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