A boy drops a stone in a 60m deep well. After how much time does he hear the splash if speed of sound is 340 m/s and g=10 m/s²
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Total time taken = 3.64 seconds
Time taken to hear the splash of water = time taken by the stone to reach the water in well + time taken by the sound of splash to reach the listener
For time taken by the stone to reach the water in the well -
u = 0
s = 60 m = depth of the well
g = 10 m/s²
Using , s = ut + 1/2 gt²
=> 60 = 0 + 1/2 × 10 × t²
=> t² = 12
=> t = √12 seconds
=> t = 3.46 seconds
For the time taken by the sound of splash to reach the listener -
v = 340 m/s = velocity of sound
s = 60 m
s = vt'
=> t' = 60/340
=> t' = 0.176 seconds
Total time taken = t + t'
= 0.176 + 3.46
= 3.64 seconds
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