Question

A boy first goes 5 m due north and then 12 m due east. Find the distanct between the initial and the final position of the boy

Answer 1

Answer:

Distance between intial and final position is 13m meters

Step-by-step explanation:

boy has started at B

distance b/w intial & final position is BC

In triangle ABC,

by pythagoreas theorem

BC^2 =5^2 + 12^2

BC^2 =25+144

BC^2 = 169

BC^2 = 13^2

BC =13m

Answer 2

Answer:

V5^2+12^2 =v169=13m Ans