Question

. A boy first goes 5 m due north and then 12 m due east. Find the distance
the initial and the final positions of the boy.

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Answer 1

Step-by-step explanation:

C = initial point

A = final point

displacement = shortest path between initial and final point.

AC = displacement

delta ABC is right angled using Pythagorean

ac^2 = AB^2 + BC^2 = 12^2 + 5^2 = AC^2

144 + 25 = AC^2 = 169 = AC^2

AC = root169 = 13m

displacement is 13m

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