a boy first goes 8m due north and then 15m due east. Find the distance between the initial and the final positions of the boy.
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8m north then 15m east forming a right angle..
perpendicular=8m
base=15m
hypotenuse =_/p sq. +b sq.
=_/8 ^2+15^2
=_/64+225
=_/289
=17m
perpendicular=8m
base=15m
hypotenuse =_/p sq. +b sq.
=_/8 ^2+15^2
=_/64+225
=_/289
=17m
varundhawanfan:
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