Math, asked by dipshikhachatte5484, 8 months ago

A boy get rupees 4 at every corrct aim at a target and losses rupees 2 for every aim missed. In a game of 16 trials he miseed 3. How much amount did he get?

Answers

Answered by itzshrutiBasrani
2

Step-by-step explanation:

____________________

Let the -

a number of targets he hit are x.

Given that a total number of targets are 100.

→ Hit targets = x

→ Missed target = 100 - x

Now,

He got Rs. 1 when he hit the target. But at the same time he losses Rs. 1 too, whenever he miss the target.

→ Hit target = 1(x)

= Rs. x

→ Missed target = 1(100 - x)

= 100 - x

Now, we have -

Rupees gain by man = Rs. x

Rupees loss by man = Rs. (100 - x)

The total amount of rupees (money) he got = Rs. 30

Rupees gain by man - Rupees loss by man = Received rupees

According to question,

x - (100 - x) = 30

x - 100 + x = 30

2x = 30 + 100

2x = 130

x = 65

•°• He hit the target 65 times.

Answered by SAMRUDDHIKITTURKAR
0

Step-by-step explanation:

he answered 16 that's 16×4=64

now he missed 3 of them that's 3×2=6

now,

64-6= 58

therefore he got 58 rupees

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