Math, asked by RPisOP344, 1 year ago

A boy get three marks for each correct sums and loses two marks for incorrect sums.He does 24sums and obtains 37marks. The number of correct sums were

Answers

Answered by Anonymous
5
Marks for each correct sum = 3
Marks for each incorrect sum = 2

Total number of sums solved = 24
Let the number of correct sums be x and incorrect sums be 24-x
So,
3x - 2( 24-x ) = 37
=> 3x - 48 + 2x = 37
=> 5x = 85
=> x = 17

Therefore the number of correct sums is 17.

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Answered by dimpu2227
1
Total no. of sums=24.
Let the no. of correct sums be x.
So, the no. of incorrect sums=24-x.
So, by the condition,
3x-2 (24-x)=37
=>3x- 48+2x =37
=>5x=85
=>x=17.
so, the no. of correct sums were 17.
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