A boy gets Rs. 2 for every 5 correct aims at a target
and loses Rs. 0.50 for every aim missed. In a game
of 8 trials he missed the aim 3 times. How much
amount does he get?
Answers
Answer:
Question:-
▪︎A boy gets Rs. 2 for every 5 correct aims at a target and loses Rs. 0.50 for every aim missed. In a game of 8 trials he missed the aim 3 times. How much amount does he get?
Answer:-
Given:
▪︎Total number of trial games = 8
▪︎Number of missed aims = 3
▪︎Rupees for correct aim = Rs.2
▪︎Rupees for missing aim = -Rs.0.50
To Find:
▪︎Total amount he get at the end of game.
Solution:
Number of times he got correct aim = 5 times
Amount he got for 5 correct aim = 5×2 = Rs.10
Amount he lost in 3 incorrect aims = 3×0.50 = Rs.1.50
Hence, total amount he hot at the end of games;
= 10-1.50
= Rs.8.50
Let’s take correct aims to be ‘a’,
fails be ‘f’.
Here, f = 3.
Therefore, as per the problem statement,
Total attempts
= a + f = 8,
Thus,
a = 8 - 3
= 5.
So, Final amount
= (2 × a) - (0.5 × f)
or, Final amount
= (2 × 5) - (3 × 0.5)
= 10 - 1.5
= 8.5
Therefore, the final amount that he would get is Rs. 8.50.