Question

A boy gets rupees 2 hours every correct aim at a target and loses rupees 0.50 for every aim missed. In a game of 8 trials he missed the aim 3 times. how much amount did he get ?
(a)10
(b)8.50
(c)12
(d)9.50​

Answer 1

Answer:

$8.50 \\ will \: be \: the \: answer$

Let’s take correct aims to be ‘a’, fails be ‘f’. Here, f=3.

Therefore, as per the problem statement,

total attempts=a+f=8, thus, a=8–3=5.

so, final amount= (2*a)-(0.5*f)

or, final amount=(2*5)-(3*0.5) =10–1.5 =8.5

Therefore, the final amount that he would get is Rs. 8.50

Answer 2

Answer:

The answer is 8.50

Step-by-step explanation:

The rupees he earned is 10

and he lost is 1.50

total rupees he earned =10-1.5=8.50