A boy goes from A to B with a velocity of
20 m/min and comes back from B to A with a
velocity of 30 m/min. The average velocity of the
boy during the whole journey is
Answers
Answered by
71
Answer:
0
Explanation:
Average velocity
As net displacement will be zero then average velocity will be also zero.
Average speed
We know,
Speed = distance/time or s = d/t
Then,
20 = d/t1
t1 = d/20
And,
30 = d/t2
t2 = d/30
Average speed = total distance/total time
= [2d]/[(d/20) + (d/30)]
= 24 m/s
Answered by
1
Given,
Velocity of boy from A to B=20m/min
From B to A=30m/min
To Find,
The average velocity of the boy.
Solution,
As its net displacement will be zero then average velocity will be also zero.
Average speed of the boy will be
We know,
Speed = distance/time or s = d/t
Then,
20 = d/t1,
t1 = d/20
And,
30 = d/t2
t2 = d/30
Average speed = total distance/total time
= (2d)/{(d/20) + (d/30)}
= 24 m/s
Hence, the average velocity of the boy during the whole journey is 24m/s.
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