A boy goes from point A to point B with a velocity of 20m/s. And comes back from point B to A with velocity of 30m/s. The average velocity of the boy during the whole journey is
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Given: A boy goes from A to B with a velocity of 20m/min and comes back from B to A with a velocity of 30 m/min.
To find: We have to find the average velocity of the boy.
Solution:
Let the distance between A and B is D meter.
A boy goes from A to B with a velocity of 20m/min.
So the time =D/20
He comes back from B to A with a velocity of 30 m/min.
So, the time= D/30.
Total time=D/20+D/30
=5D/60
Total distance traveled by the boy =2D.
Average velocity of the boy is a ratio of total distance to total time.
\begin{gathered} \frac{2D}{ \frac{5D}{60} } \\ = \frac{2 \times 60}{5} \\ = 24\end{gathered}
60
5D
2D
=
5
2×60
=24
The average velocity of the boy during the journey is 24m/min.
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