Question

A boy goes to a market 2 kilometres far from his house in 30 minutes. He comes back from market to his house in 15 minutes. Find his average velocity​

Answer 1

Answer:

0 km/h

Explanation:

As per the provided information in the given question, we have :

• A boy goes to a market 2 kilometres far from his house in 30 minutes.
• He comes back from market to his house in 15 minutes.

We are asked to calculate his average velocity.

Average velocity is defined as total displacement covered divided by total time taken.

$\longmapsto \bf { Velocity_{(avg)} = \dfrac{Total \; displacement}{Total \; time} }$

Total Displacement :

As the body comes back to its initial position, which is its house (A) after covering certain distance, his total displacement is 0 as its initial and final position is same.

Total time :

$\longmapsto\rm { Time_{(Total)} = t_1 + t_2}$

$\longmapsto\rm { Time_{(Total)} = (30 + 15) \; min}$

$\longmapsto \rm { Time_{(Total)} = 45 \; min}$

$\longmapsto\rm { Time_{(Total)} = \dfrac{45}{60} \; h}$

$\longmapsto\bf { Time_{(Total)} = \dfrac{3}{4} \; h}$

Average velocity :

$\longmapsto \bf { Velocity_{(avg)} = \dfrac{Total \; displacement}{Total \; time} }$

$\longmapsto \rm { Velocity_{(avg)} = \Bigg ( 0 \div \dfrac{3}{4}\Bigg ) \; kmh^{-1} }$

$\longmapsto \bf { Velocity_{(avg)} = 0 \; kmh^{-1} }$

∴ Average velocity is 0 km/h.