Question

a boy goes to market at an average speed of 29 kilometre per hour finding the market closed he immediately return back by the same path with the average speed of 40 kilometre per hour find the average speed and average velocity for the complete journey in the above question if the boy covers half the path during his return journey find the average speed and average velocity

Answer 1

Answer:

Distance = s in both case

T1 = s/v1 =s/29 h

T2=s/v2 =s/40 h

A) Av speed for whole trip =total distance /total time

= s+s/t1+t2

=2s km/ s/29+ s/40 h

=2s/69s/1160 km/h

=2× 1160/69 =33.62 km/h

And

B)

Displacement=0

T1=0/29 km/h

T2=0/40 km/h

Average velocity=displacement/time taken

Av=0/0/1160=0km/h because displacement is 0

Explanation: