A boy goes to market at an average speed of 29 kmh-1. Finding the market closed, he immediately
returns back by the same path with an average speedof 40 km h-1.if the boy covers half the path during his return journey ,find the average speed and average velocity
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Explanation:
Distance = s in both case
T1 = s/v1 =s/29 h
T2=s/v2 =s/40 h
A) Av speed for whole trip =total distance /
total time
= s+s/t1+t2 =
=2s km/ s/29+ s/40 h
=2s/69s/1160 km/h
=2x 1160/69 =33.62 km/h
And
B)
Displacement=0
T1=0/29 km/h
T2=0/40 km/h
Average velocity=displacement/time taken Av=0/0/1160=Okm/h because displacement is
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