Question

a boy goes to market at an average speed of 29kmh-1.finding the market closed,he immediately returns back by the same path with an average speed of 40km h-1.find the (a) average speed (b) average velocity for the complete journey.​

Answer 1

Answer:

33.62 Km/h.

0 Km/h.

Explanation:

Given :-

A boy goes to a  market at an average speed of 29 Km/h.

He returns back by the same path with a average speed of 40 Km/h since the market was closed.

To find :-

His average speed, average velocity for the complete journey.

Solution :-

Time$_1$ = Distance

• s/29 h

Time$_2$ = Distance

• s/40 h

➤ Average speed :-

⇒ Total distance/Total time

⇒  (s + s)/(s/29 + s/40)

⇒ (2s)/69s/1160

⇒ 2× (1160/69)

⇒ 33.62

∴ Average speed is 33.62 Km/h.

➤ Average velocity :-

⇒ Displacement/Total time

⇒ 0/1160

⇒ 0

∴ Average velocity is 0 Km/h.