A boy got following marks out of 90 in 5 subjects: 56, 53, 65, 74, 78. If all the marks are printed in reverse order due to mistake for ex. 65 is printed as 56, then the difference in true and appeared percentage would be
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fake percentage = (56+53+65+74+78/450)×100
=72.44%
original percentage =(65+35+56+47+87/450)×100
=64.44%
P(original marks) < P(fake marks)
therefore, original percentage is smaller than fake percentage by :- (72.44%)-(64.44%)
=8%
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