Question

A boy got twice as many sums wrong as he got right. if he attempted 51 sums in all, how many did he sovle correctly?

Answer 1

Here is your answer dear⬇️⬇️

Let the sums which got right be x and wrong sums be 2x.

So,

2x + x = 51

3x = 51

x = $\frac{51}{3}$

x = 17


Therefore, the sums which are right are 17.

Answer 2

Let the sums right be x and sums wrong be 2x.
x+2x=51
3x=51
x=17
Therefore, a boy solved 17 sums correctly.