Question

A boy had 7 marbles and lost two. How many marbles does he have now?

Answer 1

Answer:

Step-by-step explanation:

Given,

        no. of marbles boy have - 7

        no. of marbles he lost- 2

        no. of marbles he have now- 7-2= 5

         so, boy have 5 marbles left with him

        I hope this will help you

Answer 2

Answer:

Now he have 5 numbers of marbles.

Step-by-step explanation:

Given,A boy had 7 marbles and he lost 2 marbles.

So,total number of marbles = 7

and total number of lost marbles = 2

We want to here number of marbles does he have now .

By subtraction we can solve this problem.

Now remaining total number of marbles

$= 7 - 2 \\ = 5$

This is a problem of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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