A boy had twice as many sums wrong as
right. If he had 24 sums in all how many of
them were wrong:
Answers
Answered by
0
Answer:
12
Step-by-step explanation:
12 x 2 =24
12 sums were correct and 12 sums were wrong
Answered by
2
Step-by-step explanation:
r=number he got right.
w = number he got wrong.
r + w = 24
this means the number he got right plus the number he got wrong is equal to the total number of sums that he had to solve.
w = 2r
this means that the number he got wrong is twice as many as the number he got right.
since w = 2r, then replace w with 2r in the equation of r + w = 24.
you will get r + w = 24 becomes r + 2r = 24.
combine like terms to get 3r = 24.
divide both sides of the equation by 3 to get r = 8.
since w = 2r, then w = 16.
he got 8 right and 16 wrong.
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