Math, asked by saeed442, 3 months ago

A boy had twice as many sums wrong as
right, if he had 24 sums in all, how many of
them were wrong?
(A) 4
(B) 6
( 8
(D) 16​

Answers

Answered by StudiousSagar
0

Answer:

The boy had 16 wrong answers

Step-by-step explanation:

let the number of correct answers be x

and number of incorrect answers be y

As per condititon 1 :

x + y = 24                                               (1)

As per condition 2 :

2x = y                                                      (2)

By Substitution method

Substituting (2) in (1)

x + y = 24

x+ 2x = 24

3x = 24

x = 24/3

x = 8

Substituting x = 8 in (2)

y = 2x

y = 2 × 8

y = 16

Similar questions