A boy had twice as many sums wrong as
right, if he had 24 sums in all, how many of
them were wrong?
(A) 4
(B) 6
( 8
(D) 16
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Answer:
The boy had 16 wrong answers
Step-by-step explanation:
let the number of correct answers be x
and number of incorrect answers be y
As per condititon 1 :
x + y = 24 (1)
As per condition 2 :
2x = y (2)
By Substitution method
Substituting (2) in (1)
x + y = 24
x+ 2x = 24
3x = 24
x = 24/3
x = 8
Substituting x = 8 in (2)
y = 2x
y = 2 × 8
y = 16
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