a boy had twice as many sums wrong as right. if he had 24 sums in all how many of them were wrong?
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r= number he got right.
w = number he got wrong.
r + w = 24
this means the number he got right plus the number he got wrong is equal to the total number of sums that he had to solve.
w = 2r
this means that the number he got wrong is twice as many as the number he got right.
since w = 2r, then replace w with 2r in the equation of r + w = 24.
you will get r + w = 24 becomes r + 2r = 24.
combine like terms to get 3r = 24.
divide both sides of the equation by 3 to get r = 8.
since w = 2r, then w = 16.
he got 8 right and 16 wrong.
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