a boy has 3 library tickets and 8 books are of his interest. Of these 8,he doesn't want to borrow maths part 2, unless maths part 1 is also borrowed? In how many ways can he choose the 3 books to be borrowed ?
Answers
Answered by
0
if he gets both 1 nd 2 part of the maths book= 6C1 +
if he gets his first oart of math but doesnt get the second one= 6C2 +
IF he didnt get 1 nd 2 part of maths book then=6C3
adding 6C1+6C2+6C3
we get 6+15+20= 35+6
=41
Answered by
1
Step-by-step explanation:
first option is he chooses any of the books other then chemistry part 2 = 7C3 = 35
second option is he selects both the chemistry books and any other book from the remaining options = (2C2 * 6C1) = 6
he can choose in a total of 41 ways.
Similar questions