A boy has 3 library tickets and 8 books of his interest in the library. Of these 8 books, he doesn't want to borrow Chemistry part 2 unless chemistry part 1 is also borrowed. In how many ways can he choose 3 books to be borrowed?
Answers
Answered by
230
The first option is he chooses any of the books other then chemistry part 2 = 7C3 = 35
The second option is he selects both the chemistry books and any other book from the remaining options = (2C2 * 6C1) = 6
So he can choose in a total of 41 ways.
The second option is he selects both the chemistry books and any other book from the remaining options = (2C2 * 6C1) = 6
So he can choose in a total of 41 ways.
Similar questions