Question

A boy has 7 different toys how many ways he can choose one or more toys

Answer 1

He can choose any one toy in 7 different ways i.e. 7c1
and 2 of them can be chosen in 7c2 woys
so total would=7c1+7c2+7c3+7c4+7c5+7c6+7c7
= 7+21+35+35+21+7+1=127

Answer 2

Answer:

=7c1+7c2+7c3+7c4+7c5+7c6+7c7

= 7+21+35+35+21+7+1=127

Step-by-step explanation:

Correct option is D)

For each of the things there is two possibilities, it will be selected or rejected.

So each of the things will have two choices.

Therefore total number of possibilities is =2

7

=128.

And there will be only one case when all things will be rejected.

Hence, number of ways of selecting one or more out of 7 things is =2

7

−1=127