Question

A boy has a few coins of denominations 10 paise, 20 paise and 25 paise in the ratio 10 : 15 : 6. Then, the possible value of the denomination=?

Answer 1

Answer:

Step-by-step explanation:Let the possible number of coins be 10x, 15x and 6x. 0.1×10x+0.20×15x+0.25×6x=5.5x. We can put x = 11 it is multiple of 5.5

Answer 2

Given:

Ratio of the coins= 10:15:6

Types of denomination is 10 paise, 20 paise, 25 paise.

To find:

The possible value of denomination.

Explanation:

Let the number of 10 paise coins be 10x.

Let the number of 20 paise coins be 15x.

Let the number of 25 paise coins be 6x.

The value of 10 paise coins$=10\times 10x=100x$

The value of 20 paise coins$=15\times 20x=300x$

The value of 25 paise coins$=6\times 25x=150x$

On totaling the value of given denominations we get,

$100x+300x+150x=550x$

Hence, the possible value can be 550 paise or 5.5 rupees.

There can be many values possible which will be multiple of 5.5 rupees or 550 paise.

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