A boy has rs728 in the denomination of Rs 2 notes, Rs 5 notes and Rs 10 notes in the ratio of 3:2:4 , respectively. What is the total number of notes he has?
Answers
Answered by
1
total sum of money = 728
ratio = 3 : 2:4
let the number of notes be x
value of 2 rupees notes = 3×2 × x
= 6 x
value of 5 rupee note = 5×2×x
= 10 x
value of 10 rupee note = 10×4×x
= 40 x
we can say that 728 = 6 x +10 x +40 x
=> 728 = 56 x
=> x = 728/56
=> x = 13
no. of 2 rupee notes = 13×3 = 39
no. of 5 rs.= 13×2= 26
no. of 10 rs. = 13 ×4 = 52
totl notes = 52 + 26+ 39 = 117
ratio = 3 : 2:4
let the number of notes be x
value of 2 rupees notes = 3×2 × x
= 6 x
value of 5 rupee note = 5×2×x
= 10 x
value of 10 rupee note = 10×4×x
= 40 x
we can say that 728 = 6 x +10 x +40 x
=> 728 = 56 x
=> x = 728/56
=> x = 13
no. of 2 rupee notes = 13×3 = 39
no. of 5 rs.= 13×2= 26
no. of 10 rs. = 13 ×4 = 52
totl notes = 52 + 26+ 39 = 117
Similar questions