Question

A boy has to complete 48 maths problems,but he has completed only

of the total problems.Find the number of problems completed by

5/8



him and also the number of problems he still has to complete.​

Answer 1

thanks for the points thankss

Answer 2

Answer:

This is a simple straightforward question wherein we must just follow steps 1 to 3 in order to obtain the answer.

STEP 1: Calculate how much work each person does in one hour.

Jack → (1/3) of the work

John → (1/5) of the work

STEP 2: Add up the amount of work done by each person in one hour.

Work done in one hour when both are working together = 

STEP 3: Calculate total amount of time taken when both work together.

If they complete  of the work in 1 hour, then they would complete 1 job in  hours.

Example 2.

Working, independently X takes 12 hours to finish a certain work. He finishes 2/3 of the work. The rest of the work is finished by Y whose rate is 1/10 of X. In how much time does Y finish his work?

Solution:

Now the only reason this is trickier than the first problem is because the sequence of events are slightly more complicated. The concept however is the same. So if our understanding of the concept is clear, we should have no trouble at all dealing with this.

‘Working, independently X takes 12 hours to finish a certain work’ This statement tells us that in one hour, X will finish  of the work.

‘He finishes 2/3 of the work’ This tells us that  of the work still remains.

‘The rest of the work is finished by Y whose rate is (1/10) of X’ Y has to complete  of the work.

‘Y's rate is (1/10) that of X‘. We have already calculated rate at which X works to be . Therefore, rate at which Y works is .

‘In how much time does Y finish his work?’ If Y completes  of the work in 1 hour, then he will complete  of the work in 40 hours.