A boy has to lift a load of 50 kg to a height of 1 m.(a) what effort is required if he lifts it directly?take g=10N/k g.(b)the boy can exert a maximum effort of 250N so he uses an inclined plane to lift the load up. what should be the minimum length of the plank used by him.explain.
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HEllo !
Load = 50 × 10 = 500 N
a) Effort = 50 × 10 ( if he lifts it up directly)
b) Effort = 250 N
MA = Hypotenuse / Height = Load / Effort
Height = 1 m
Hypotenuse /1 =500/250
Hypotenuse = 2 metre
The Length of the Planck should be 2 m
I hope my answer is correct and it satisfies u !!
Thank you !
Load = 50 × 10 = 500 N
a) Effort = 50 × 10 ( if he lifts it up directly)
b) Effort = 250 N
MA = Hypotenuse / Height = Load / Effort
Height = 1 m
Hypotenuse /1 =500/250
Hypotenuse = 2 metre
The Length of the Planck should be 2 m
I hope my answer is correct and it satisfies u !!
Thank you !
kvnmurty:
:) good
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