A boy holds a 50 N weight at arm's length for
10 s. This arm is 1.5 m above the ground. The
work done by the boy on the weight while he is
holding it, is
(1) Zero
(2) 20 J
(3) 40J
(4) 60 J
Answers
Answered by
2
The problem is solved as below:
Given:
Weight = w = 50 N
time = t = 10 s
height = 1.5 m
To find:
Work done = W =?
Solution:
As we know the work done formula is
W = F.d cosθ
where F is the force and d is the displacement.
Since the boy is just standing so there is no displacement.
W = F.(0) cosθ
W = 0
So the work done by the boy is zero.
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