Question

A boy holds a pendulum in his hand while standing
at the edge of a circular platform of radius r rotating
at an angular speed o. The pendulum will hang at
an angle with the vertical so that :-
(Neglect length of pendulum)
(1) tan 0 = 0
(2) tano - 0ʻr?
g
(3) tan e = ro?
(4) tan e = a​

Answer 1

Answer: tan theta = w2r/g

Explanation:

Answer 2

Answer:

tanθ=ω^R/g.

Explanation:

Since, the boy is rotating the string with the angular speed of ω. So, the string will be having a tension T in the upward direction. So, the components will be given as Tsinθ= mv^2/R which will be Tsinθ=mω^2R where θ is the angle with the vertical.

Again, the Tcosθ will be equal to mg. When we divide both of the equation we will get that tanθ=ω^R/g. Where R is the radius of the circle of rotation.