a boy increases his speed to 9/5 times of his original spped. by this he reaches his school 30 minutes before the usual time. how much time does he takes usually?
A) 70.50 Min
B) 54 Min
C) 66.67 Min
D) 67.50 Min
Answers
Answered by
7
Answer:
the answer is
B. 54 minutes
Step-by-step explanation:
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Answered by
3
Answer:
67.50
Step-by-step explanation:
d=s×t
t=d/s
t=9/5×(t-30)
5t=9T-270
9t-5t=270
4t= 270
t= 270/4
t= 67.50 min
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