A boy is 10 years old and his mother is 37 years old. In how many years' time will the mother be twice as old as her son?
Answers
Answered by
20
Answer:
Suppose after x years the mother is twice as old as her son.
Mother is now 37 years old. So after x years she will be 37 + x years.
Son is now 10 years old. So after x years he will be 10 + x years.
Therefore we have 37 + x = 2(10 + x)
=> 37 + x = 20 + 2x
=> x = 17.
So after 17 years mother will be twice as old as her son.
Mother' age after 17 years = 37+17=54
Son's age after 17 years = 10+17 = 27.
Clearly, 54 is twice 27.
Answered by
27
Given:
- Current age of a boy = 10years
- Current age of mother = 37years
To Find:
- The years' time at which the mother be twice as old as her son
Solution:
Let the time taken be x years
So, atq
=> 37 + x = 2(10 + x)
=> 37 + x = 20 + 2x
=> 2x - x = 37 - 20
=> x = 17
So, in 17 years, the mother will be twice as old as her son.
Verification:
Age of son after 17 years = 10 + 17 = 27years
Age of mother after 17 years = 37 + 17 = 54years
And we know that, 27*2 = 54
Hence proved too!!
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