Question

A boy is 26 years younger than his father . In 3 years ,his age will be 1/3 of his father's age . Find the boy's present age​

Answer 1

Step-by-step explanation:

Let the boy's age be x

then father's age would be x+26

age of boy after three years = x+3

and age of father after three years = x+29

A/Q. after three years boy's age would be 1/3 of his father's

so,. x+3 = x+29/3

3x+9 = x+29

2x = 20

x= 10

Hence boy's age would be 10 years

Answer 2

Answer:

The boy is presently 10 years old.

Step-by-step explanation:

Gívєn -

Boy is = 26 years younger than is father

In 3 years ,his age will be = $\dfrac{1}{3}$ of his father's age.

Tσ fínd -

The boy's present age

Sσlutíσn -

✯ Let the ages be -

• Father as x
• Son as (x - 26)

$\rule{300}{1.5}$

✯ After 3 Years =

• Father will be (x + 3)
• Son will be (x - 26) + 3

$\rule{300}{1.5}$

✯ According to the Question -

After 3 Years boy's age will be 1/3 of his father's age .

$\bf{\implies} \: (x - 26) + 3 = \dfrac{1}{3} \: of \: (x + 3)$

$\sf{\implies} \: x - 26 + 3 = \dfrac{1}{3} \: \times \: x + 3 \\\sf{\implies} \: x - 23= \dfrac{x}{3} \: + 3 \\ \sf{\implies} \: 3(x - 23)= x + 3 \\ \sf{\implies} \: 3x - 69= x + 3 \\\sf{\implies} \: 3x -x = 3 + 69 \\ \sf{\implies} \:2x =72 \\ \sf{\implies} \: x = \frac{72}{2} \\ \sf{\implies} \:x = 36$

Father's present age = 36

$\rule{300}{1.5}$

✯ Son's present age =

$\sf{\implies} \:(x - 26) \\ \sf{\implies} \:36 - 26 \\ \sf{\implies} \:10$

Son's present age = 10 Years

$\therefore$ The boy is presently 10 years old.