Math, asked by rekharane187, 1 year ago

A boy is 30yrs younger than his father 10yrs later father will be twice the boy find their ages at present

Answers

Answered by karnatiAkshaya
0
At present ,
Boys age=x
Fathers age=30+x

After ten years,
Boys age =x+10
Fathers age =30+x+10


According to the statement ,
2(x+10)=30+x+10
2x+20=40+x
2x-x=40-20
x=20

At present
The boys age =20
Fathers age=50


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