Question

A boy is 5 times as old as his sister .two years ago the sum of the squares of their ages was 170.find the present age of sister​

Answer 1

Step-by-step explanation:

Present age of sister=X years and boy=5x years.

2 years ago,sister=x-2 and boy=5x-2 years.

ATQ,(x-2)^2+(5x-2)^2=170