Question

A boy is at a distance of 60 m from a tree, makes an angle of elevation of 60° with the top of the tree. What is the height of the tree ? *
2 points
60.3 m
60√3 m
60 m
60√2 m​

Answer 1

(60√3)/2

height AB= BC SinC

= 60m √3/2

Answer 2

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