Question

A boy is executing simple Harmonic Motion. At a
displacement x its potential energy is E₁ and at a
displacement y its potential energy is E₂. The potential
energy E at displacement (x + y) is
(a) √E = √E₁ - √E₂ (b) √E = √E₁ + √E₂
(c) E = E₁ + E₂ (d) E = E₁ - E₂​

Answer 1

Answer:

B)√E=√E1+√E2

Step-by-step explanation:

Potential energy at x=E

1

=

2

1

Kx

2

x=

K

2E

1

Potential energy at y=E

2

=

2

1

Ky

2

y=

K

2E

2

Potential energy at x+y=E=

2

1

K(x+y)

2

E=

2

1

K(

K

2E

1

+

K

2E

2

)=(E

1

+E

2

)

2

E

=E

1

+E

2

.

Answer 2

Answer:

Option b is correct answer.