Question

A boy is flying a kite with a string of length 100 m . If the string is tight and the angle of elevation of the kite is 26° 32' , find the height of the kite correct to one decimal place ( ignore the height of the boy ) .​

Answer 1

Answer:

882 is my answer. hope it will help you

Answer 2

Answer:-

• the height of kite is 44.7m

To Find:-

• the height of the kite correct to one decimal place.

Given:-

• Angle of elevation of the kite = 26° 32'

• lenght of string = 100m

Consider:-

• AB as the height of the kite A and AC as the string,

• → AC = 100

• → Take AB = x

In right triangle ABC

• => Sin∅ = $\frac{AB}{AC}$

$\:\:\:Substituting\:the\:values,$

• ⇒sin26° 32′ = $\frac{x}{100}$

• ⇒0.4467 = $\frac{x}{100}$

• ⇒x = 100 × 0.4467

• ⇒x = 44.67 ≈ 44.7m

Hence, the height of the kite is 44.7 m.