A boy is flying a kite with a string of length 100 m. if the string is tight and the angle of elevation of the kite is 26° 32`, find the height of the kite correct to one decima place (ignore the height of the body)
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let the angle of kite =h
then
sin 26° 32`=h/100
h= 100× sin 26° 32'
since
sin (26°)=0.438371
so
h= 100× 0.438371
47.8371
then
sin 26° 32`=h/100
h= 100× sin 26° 32'
since
sin (26°)=0.438371
so
h= 100× 0.438371
47.8371
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