A boy is flying a kite with an angle of elevation of 60° and at a height of 200m . what should be the lenght of the threaad
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HII MATE HERE IS YOUR ANSWER
theta = 60°
sin 60°= height of kite / length of thread
√3 /2 = 200 / length of thread
length of thread = 200 × 2 / √3
= 400 / 1.732
. =230.94 m
I HOPE IT WILL HELP YOU
theta = 60°
sin 60°= height of kite / length of thread
√3 /2 = 200 / length of thread
length of thread = 200 × 2 / √3
= 400 / 1.732
. =230.94 m
I HOPE IT WILL HELP YOU
Bajaj2403:
Well it is 230.93333
And when you round it you get 230.93
Answered by
1
Answer: 230.93 m
Step-by-step explanation:
Let the height be AC(perpendicular)
Let the length be AB(hypotenuse)
Sin 60°=AC/AB
√3/2=200/AB
=AB=200×2/√3
AB=400/√3
Rationalising
AB=400√3/3
AB=400×1•732/3
AB=4×173•2/3
= 230.93m(Ans)
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