A boy is going from one place to other. He goes 4m north and then 3m east. Find the displacement of the boy from his starting point?
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displacement of boy is 5 metre
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let A be the starting point
now the boy covers 4m towards north
take the point to be B
AB = 4m
now he goes 3m towards east
take the point to be C
BC = 3m
now the displacement will be AC (shortest path)
so by pythagoras theorem(triangle will be right angled)
AC=√(AB)^2 +(BC)^2 m
=√(4)^2 + (3)^2 m
=√16+9 m
=√25 m
= 5 m
answer is 5 m
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